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6b^2-b-70=0
We add all the numbers together, and all the variables
6b^2-1b-70=0
a = 6; b = -1; c = -70;
Δ = b2-4ac
Δ = -12-4·6·(-70)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*6}=\frac{-40}{12} =-3+1/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*6}=\frac{42}{12} =3+1/2 $
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